Zipping files two by two

I have a directory full of files ending with different extensions, how would I list/select only the files ending with .in and corresponding .out that share the same basename?

e.g.

file1.txt file1.in file2.in file3.in file2.out file3.out

What I want to select from these files are:

file2.in file2.out file3.in file3.out

I have 4 files file1,file2,file3,file4.I have to read each word from file1 and return the count of it in all the 3 remaining files as a whole.How to do dat?? eg: file1 this is a cat file2 this is a mat file3 this is a rat file4 cat mat rat Output: this:2 is:2 a:2 cat:1

For Suppose, i have installed a package having files file1, file2 and file3. After installation i have removed file3.

But "rpm -qf file3" is giving the package name, even file3 was not there. And also "rpm -ql package" is also displaying all 3 files.

How can i update rpm about that package to display only available files i.e. file1 and file2 when queried with "rpm -ql"

Hi ,

I have two files File1 and File2.In First file i have table names abc def cfg

In second file i have the sql commands for e.g replace view def.test1 for access select * from abc.test1;

I have to find the common words from File1 and File2 and printing it in File3 the grep command i am using is

grep -o -f File1 File2|sort|uniq > File3

The problem i am facing is , if i run the above g

Hi guys,

I want to compare file1 and file2 using awk. And then using the output to file3.

file1 4 3 2

file2 5 10 1

So the output in file3 would be 1 7 1

Any idea on how to do this? I'm a newbie:oops:

Thx in advance

How do I keep a file pattern from evaluating?

I want to pass in a file pattern to a script as a parameter, and then use that pattern in subsequent statements, but I can't get the pattern to not evaluate before I use it.

For example, if I have 3 files called file1.txt, file2.txt and file3.txt and in my script I have something like this:

num=`ll $1 | wc -l`

and I pass file*.txt in as my para

I have 2 directories

DIR1 contains file1, file2 DIR2 contains file1, file3

Is there a way to replicate DIR1 to DIR2. means, if i give,

cp -r DIR1/* DIR2

file1 in DIR2 gets replaced with file1 in DIR1. file2 in gets copied to DIR2. file3 remains untouched.

But, i need DIR2 to be the exact replica of DIR1.

I have been using awk to sum up multiple files, this is used to sum up the summary of server log parsing values, it really does speed up the final overall count but I have hit a minor problem and the typical examples I have hit on the web have not helped.

Here is the example:

cat file1 aa 1 bb 2 cc 3 ee 4

cat file2 aa 1 bb 2 cc 3 dd 4

cat file3 aa 1 bb 2 cc 3 ff 4

And the script:

cat test.

Hi All, I have two directories that has some files, some of the files are common to both of them like :

Code: ls -l dir1

file1 file2 file3

Code: ls -l dir2

file1 file2 file3 file4 file5 Now i want to get the files from dir2 that are not present in dir1 (means i want to get file3,file4,file5).