Writing bash scripts

Hi friends you can solve my question about make 3 shell scripts?

Quote:

Write a shell script such that, given multiple files as arguments, showing, for each of them, his name and the number of lines it contains. Try it with any file.

2.

Hi

I have 1000 files labelled data1.txt through data1000.txt. I want to write a script that prints out the number of lines in each txt file and outputs it in the following format:

Column 1: number of data file (1 through 1000) Column 2: number of lines in the text file

Thanks!

My Bash-Script should accept arguments and options. Moreover arguments and options should be passed to another script.

The second part I've solved:

for argument in "$@"; do options $argument done

another_script $ox $arguments

function options { case "$1" in -x) selection=1 -y) selection=2 -h|--help) help_message;; -*) ox="$ox $1";; *) arguments="$arguments $1";; esa

I have a text file with courses that looks like this:

csc 4567 - Computer Programming This course is about stuff...blah blah blah 4.0000 credit hours

I need to write a bash script that takes the text file and extracts the necessary information to display course number, course name, course credit hours. No spaces, just commas between. Course credit hours as whole number.

Hello please kindly solve these doubts i have about the following scripts

Code: Script 1 //Shell script that accepts arguments and prints them in reverse order// echo "number of arguments" len=$#; while [ $len -ne 0 ] do eval echo \$$len len=`expr $len - 1` done

--------- Output $sh test.sh a b b a 1.what is \$$len.what is the significance of the escape sequence

Script 2

Cod

Hello. I'm new to Perl and I am not sure how to interpret command line arguments in the program. I am writing a program similar to the Unix utility 'tail' and need to check if first argument is '-1' ([dash]1) or any arbitrary number of lines to output. How would I write an 'if' statement to check for the dash (-) and a number?

I've been writing a number of bash scripts lately which get variables from a parameter or from a file.

I have two (Ubuntu Linux) bash scripts which take input arguments. They need to be run simultaneously. I tried execve with arguments e.g.

char *argv[10] = { "/mnt/hgfs/F/working/script.sh", "file1", "file2", NULL };

execve(argv[0], argv, NULL)

but the bash script can't seem to find any arguments at e.g. $0, $1, $2.

What's missing?

HI guys i am new to programing world, i have found one more wish with command line argument.

I have a shell script say one.sh ,

file_name=$1 //first argument file name(two.sh) //connect to ftp and download $file_name bash $file_name $2 $3 $4 //2nd 3rd and 4th arguments

say $file_name "actual name is two.sh, in two.sh

..... ..... chmod 777 script.sh