To match a word one can use
\v(\w+)
From the vim help :h \w:
\w word character: [0-9A-Za-z_]
This works exactly as described in the manual. However, I want to
match words that contain characters beyond a-z, e.g.
prästgården.
4 Pics 1 Word - What's the Word? Youve got a set of 4 pics that have something in common! Link scrambled letters and type 1 word!
Test your skills and vocabulary, exercise your logic and move on to harder levels of this quiz game!
How far can you go to find what's hidden behind these pictures?
I'm using SearchManager to search for words in a database. It works fine with standard letters, but when using language specific letters (č,ž,š), it only finds the word if the letter is in the middle of the word. If the letter is in the beggining of the word, it returns that there are no mathes (but they exist in the database). Can the encoding of the SearchManager be changed?
This is a pretty basic question, but I can't get my head around it. I'm learning Linux and one of the questions i've been given is;
*The word sentimentalment includes the same three characters (e.g. "ent") which appear three times. The word "blayblapblam" also contains
the same three characters repeated three time (e.g.
dash related feature request
New page= camelCaseMotion =
Great script. But IMO it lacks one feature: for some file types dash character is considered a keyword (see :h iskeyword), which makes it a part of a word (just like underscore). But the script acts as if dashes were a regular letter characters in such cases.
I am trying to count the occurrences of ALL words in a file. However, I want to exclude certain words: short words (i.e. <3 chars), and words contained in an blacklist file. There is also a desire to count words that are capitalized (e.g. proper names). I am not 100% sure where the line on capitalization is; i.e. do we count the first word of a sentence differently?
I had a command which would work through a text file, count all the occurrences of the words and print it out like this:
remy@box $˜ magic-command-i-forgot | with grep | and awk | sort ./textfile.txt
66: the
54: and
32: I
16: unix
12: bash
5: internet
3: sh
1: GNU/Linux
So it does not search line-by-line, but word by word, and it does it for all the words, not just for 1 word.
hello everyone
I'm writing a bash script and I have to parse a line that looks as follows:
Code:
a/ b:4 word=egg things.?/things2//
no matter what other words or characters exist in the line,I only want to keep the word(or number) that comes after the =
in this case the word is "egg".
Is there a way doing this by using sed?
My target is to replace any word/string/Any characters in file
with new word/string according to the following rules:
If numeric characters on the left side of word/string then we not replace the word
If numeric characters on the right side of word/string then we not replace the word
remark - numeric means any number or [a-z] or [A-Z]
The following Example described file before , and file a
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