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shell script did read file using cat

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http://stackoverflow.com – #!/bin/bash # Reading Manthan Status echo "Manthan cat started" cat /var/www/symmetric-ds-3.1.6/bin/my_mon.txt | while read LINE do echo "Inside my loop" echo "$LINE" if [ "$LINE" == "false" ]; then echo "startedif_my" sudo lsof -n -i:8082 | grep LISTEN | awk '{ print $2 }' | uniq |sudo xargs kill -9; sleep 30; sudo sh /var/www/symmetric-ds-3.1.6/bin/sym --port 8082 --server; break fi done #Reading Panel Status echo "Panel cat started" cat /var/www/symmetric-ds-3.1.6/bin/panel_mon.txt | while read LINE do echo "Inside panel loop (HowTos)

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Submitted by linuxletgo on 02/13/2013

Stories similar to shell script did read file using cat

Cannot start a script 13 weeks 2 days ago

#!/bin/bash value=$(<man.txt) echo "$value"

if [ "$value" == "true" ]; then echo "startedif_manthan" ps -ef|grep sym |awk '{ print $2 }'|sudo xargs kill -9; sleep 30; sudo sh /var/www/symmetric-ds-3.1.6/bin/sym --port 8082 --server; fi

Hi There, I have this script killing a process and restart the script in some time.

Cannot start a script 13 weeks 2 days ago

#!/bin/bash value=$(<man.txt) echo "$value"

if [ "$value" == "true" ]; then echo "startedif_manthan" ps -ef|grep sym |awk '{ print $2 }'|sudo xargs kill -9; sleep 30; sudo sh /var/www/symmetric-ds-3.1.6/bin/sym --port 8082 --server; fi

I have this script killing a process and restart the script in some time.

#!/bin/bash value=$(<man.txt) echo "$value"

if [ "$value" == "true" ]; then echo "startedif_manthan" ps -ef|grep sym |awk '{ print $2 }'|sudo xargs kill -9; sleep 30; sudo sh /var/www/symmetric-ds-3.1.6/bin/sym --port 8082 --server; fi

I need to run above script in cron. Will it execute in cron without password?

Any suggestions?

#!/bin/bash value=$(<man.txt) echo "$value"

if [ "$value" == "true" ]; then echo "startedif_manthan" ps -ef|grep sym |awk '{ print $2 }'|sudo xargs kill -9; sleep 30; sudo sh /var/www/symmetric-ds-3.1.6/bin/sym --port 8082 --server; fi

I need to run above script in cron. Will it execute in cron without password?

Any suggestions?

#!/bin/bash value=$(</var/www/sym_monitor/manthan.txt)

if [ "$value" == "true" ]; then

ps -ef|grep sym |grep -v grep |awk '{ print $2 }'|sudo xargs kill -9; cd /var/www/symmetric-ds-3.1.6/bin; sleep 30;

(sudo ./sym --port 8082 --server);

fi

I'm trying to run the above script every 10 mins using cron.

#!/bin/bash

# Reading

cat /home/radiare/Desktop/first.txt | while read LINE

do if [ "$LINE" == "false" ]; then echo "Inside first loop" break fi done

cat /home/radiare/Desktop/second.txt | while read LINE

do if [ "$LINE" == "false" ]; then echo "Inside second loop" break fi done

In ubuntu client, I could able to execute this script and echo inside if statements are properly working.

Hi I have a file which I am reading line by line and processing it. But the last line is not getting read in the file loop until I put an enter in the end.

Code: #!/bin/ksh -p v_org_id=${P1} FILE=${P2} NEW_FILE_NAME=$APPLPTMP/b1.txt BAKIFS=$IFS IFS=$'\n' exec 0<"$FILE" echo "File to be processed.....: ${FILE}"  while read -r line do v_initial=`echo "$line&qu

I am trying to read user and server details from file tempo.txt and then check the disk space usage of the file system on that unix account using another script server_disk_space.sh.But I am not able to figure out why while loop is only working for first line and for loop is working fine.Please help me understand this.

Using while loop

#!/usr/bin/ksh while read line do r1=`echo $line | cut -d"

For class I need to write a Bash script that will take the output from ispell and when I try and request user input inside the while loop it just saves the next line of the file as the user input.

How could I go about requesting user input in the while loop?

#!/bin/bash #Returns the misspelled words #ispell -l < file

#define vars ISPELL_OUTPUT_FILE="output.tmp"; INPUT_FILE=$1

ispell -l &lt