Sed delete blank lines upto first pattern match

Hi everyone, I am new to shell scripting, and would appreciate your help on following problem.

I need to search a file for a pattern, then get the number of each line that matches the given pattern. Then I need to search those specific line numbers from the first file in a second file and print the entire lines.

I tried with grep -n 'pattern' from the first file, which gives me:

21: pat

I would like to recursively list all files in a directory which match a given input pattern using ls. (Oh, and this is in Bash).

The only way I can think of to do this using ls is to shopt -s extglob and then use the ls --ignore=pattern option with the extended glob negate pattern !( pattern-list ).

Input file1 is: -----

dog 123 4335 cat 13123 23424 deer 2131 213132 bear 2313 21313

I give the match the pattern from in other file ( like dog 123 4335 from file2).

I match the pattern of the line is dog 123 4335 and after print all lines without match line my output is:

file1 :

cat 13123 23424 deer 2131 213132 bear 2313 21313

If only use without address of line only use the pa

In a bash script using sed how can I remove a block of lines beginning with -pattern a- and ending with -pattern b- where the the contents contains -pattern c- ( or does NOT contain -pattern c-)?

So :

line 1 -pattern a- line 2 line 3 -pattern b- line 4 -pattern a- line 5 -pattern c- line 6 -pattern b-

In this example I want to remove lines 4,5 and 6 (or remove 1,2 and 3 for not cont

Hi friends,

I am looking for sed command/script that would search for a given fixed pattern on odd lines and then if it matches, prints the matching pattern and the next line.

Pipe binary file matches grep results to file I am using grep to match a pattern, but the output is strange.

Code: $ grep -r -o "pattern" * Gives me:

Code: Binary file foo1 matches Binary file foo2 matches Binary file foo3 matches To find the lines before/after, I then have to use the following on each file:

Code: $ strings foo1 | grep -A1 -B1 "pattern" Ho

What I try to accomplish with 'sed' is to remove a line if the pattern match. and adding a line if pattern doesn't match.

But how could I make this? Thanks in advance

Example: I want this to use this line in Crontab:

*/1 * * * * script 1 test

With a other script I want to remove this line if this pattern is there, and otherwise, if pattern is not matching then add this line.

Hi I know sed and awk has options to give range of line numbers, but I need to replace pattern in specific lines Something like sed -e '1s,14s,26s/pattern/new pattern/' file name Can somebody help me in this....

I am fine with see/awk/perl Thank you in advance

I need to remove lines from a text file based on pattern but I need to keep the first n lines of that pattern.

Input

% 1 % 2 % 3 % 4 % 5 text1 text2 text3

output

%1 %2 text1 text2 text3

I used sed /^%/d file but it deletes all the lines starting with %, sed 3,/^%/d doesn't help either. I need to keep first n lines of the pattern and delete the rest