I have a list of relative paths such as this:
dir1
dir2
dir2/dir3
dir2/file1
dir3/file2
dir3/dir4
dir3/dir4/file3
In the example above, the specifier dir2/file1 (for example) is redundant, because the dir2 entry would include this file.
Want I want to do, essentially, is remove redundant paths from a given list of paths.
Hello experts,
I am exploring parameter expansion, and trying to cut the fields in a URL.
Following is the requirement:
I have
// abc.nnt /dir1/dir2/dir3/dir4/somefile.java
What i need to get is the path after dir3, and dir3 will be passed.
output that i need is dir4/somefile.java.
I am trying to use like
path="https://abc.com/dir1/dir2/dir3/dir4/somefile.java"
sho
Hi,
I'm on a Linux machine with a bash shell.
hi ,
please help me in this context
pkg1_name="/dir1/dir2/dir3/pkg1.txt"
pkg2_name="/dir1/dir2/dir4/pkg2.txt"
.
.
.
input to the script is pkg1 or pkg2 or ...
i have used pkg variable to save input i.e.
pkg=$1
now i need the following
result=`awk something ${pkg}_name ` for each file
but the output is showing error as
pkg1_name : no such file or d
Iam trying to load the full path of multiplie files in the same directory to an array if the filenames matches a pattern.
I have 2 directories
DIR1 contains file1, file2
DIR2 contains file1, file3
Is there a way to replicate DIR1 to DIR2.
means,
if i give,
cp -r DIR1/* DIR2
file1 in DIR2 gets replaced with file1 in DIR1.
file2 in gets copied to DIR2.
file3 remains untouched.
But, i need DIR2 to be the exact replica of DIR1.
Hi,
My below cgi script works fine from the command line but not working from the web browser.
#!/usr/bin/perl
use File::Copy;
use CGI;
print "Content-type: text/html\n\n";
print "<html><head><title>LOGS";
print "</title></head>";
print "<body bgcolor=#95B9C7 link=black>";
$infile="/home/jaindin/jaindin_PerlCGI/
HI I ma using perl programming
my perl is like this
Code:
$InputFile = $ENV{UDE_TMP} .
I want to check access rights permissions not for 'user', not for 'group', but for 'others'.
I want to do it by system command in which i want to use 'ls -l' and 'awk' command.
I have written the following program :
#!/usr/bin/local/perl
#include <stdlib.h>
system ("ls -l | awk '/^-......r../ {print $9 " is readable for others}' ");
system ("ls -l | awk '/^-.......w.
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