Hello there, I'm not getting the result's I want with my code.
So this is my table:
P_ID Latitude Longitude
9001 15 10
9002 23 54
9003 2 23
9004 23 12
9005 54 23
And here is my code:
//connect
//ordering the latitude
$query="SELECT Latitude FROM Position ORDER BY Latitude ASC";
I want to edit/change the value of a specific column value with PHP. For example, let's say that I have thousands of records and I want to change every record's column value to 1. How would I do this in PHP?
I have a problem with an ugly query. The query itself isn't so bad, the indexes are used and it is optimized.
Currently I have a perl script that accesses our database, performs certain queries and prints output to the terminal. Instead, I would like to output the results into a template latex file before generating a pdf. For most of my queries I pull out numbers and store these as scalar variables (eg how often a particular operator carries out a given task).
We have a MySQL 5.1.52 Percona Server 11.6 instance that suddenly started logging every single query to the slow query log. The long_query_time configuration is set to 1, yet, suddenly we're seeing every single query (e.g. just saw one that took 0.000563s!). As a result, our log files are growing at an insane pace.
It is easy to query all the words start with an initial character in English, for example to query all the words start with "a", we execute this query:
SELECT * FROM table WHERE word LIKE 'a%';
We can get results like "an", "at", "after"....
But it is not the same in Korean, because a Korean word is considered as a single Unicode character,
so this query:
SELECT * FROM table WHERE word LIKE
hii i've three text views
source[userinput]
destinatin[usrinput]
display[to display the resultant query]
getting from user input and how wil i apply it in query.help me pls.
and how to display multiple columns(resultant query)in one textview(display)
query="select * from table where places in('x','y');
how should i declare the string x and y n java swing to get userinput from the textvie
Hi I have a problem with my android application. I want to use sqlite database for my application.I have written this query for searching in my database and I see the result, but when I change LIKE to = without "%" , I see force closed on my device and emulator. what is the problem do you think?
cursor = db.rawQuery("SELECT _id, firstName, lastName FROM Dic WHERE firstName LIKE?
I'm in a problem with sqlite.
I put my pre-loaded sqlite database on my application, everythings works fine, the connection is Ok, the existence of the database is ok. But, when i query with select some rows return empty data in just one column.
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