Need help to read command line arguments?

I want create a script with default arguments, of manner how some commands display default arguments pressing tab button in linux

In first instance I want to catch the tab button with the command trap, but it is not a correct way since the tab button shall trapped by the shell before to execute the script and no after

the questions are, How catch the tab button in the shell before execute t

I have a shell script that takes 2 arguments.

1. The problem statement, all variables and given/known data:

Problem 1:

I need to create a shell script the takes three arguments and echo's out "There once was a ____that____who like to_____" The arguments go where the blanks are.

Problemt 2:

-Do an LS and store the listings in a file

-Open the file in emacs.

HI guys i am new to programing world, i have found one more wish with command line argument.

I have a shell script say one.sh ,

file_name=$1 //first argument file name(two.sh) //connect to ftp and download $file_name bash $file_name $2 $3 $4 //2nd 3rd and 4th arguments

say $file_name "actual name is two.sh, in two.sh

..... ..... chmod 777 script.sh

Hi friends you can solve my question about make 3 shell scripts?

Quote:

Write a shell script such that, given multiple files as arguments, showing, for each of them, his name and the number of lines it contains. Try it with any file.

2.

I run the script - my_script.ksh as process with 5 long arguments

on my solaris/linux machine ( example 1 ) ,

Later I verify the process by

ps -ef | grep my_script.ksh

I don't understand way I not get the all arguments from ps -ef ? , ( see example 2 )

or maybe ps command have limitation to display a long line ?

Under Ubuntu 11.10 and repository Codeblocks, I cannot set program command line arguments in Project - Set Programs Arguments

If you look carefully at the line beneath Program arguments: I can see what looks like a one pixel high text entry box

I can work round by hacking the project.cbp file and adding a line <Option parameters="-t nt5002" /> but this is messy.

Hello please kindly solve these doubts i have about the following scripts

Code: Script 1 //Shell script that accepts arguments and prints them in reverse order// echo "number of arguments" len=$#; while [ $len -ne 0 ] do eval echo \$$len len=`expr $len - 1` done

--------- Output $sh test.sh a b b a 1.what is \$$len.what is the significance of the escape sequence

Script 2

Cod

Hi All,

I want to pass few dynamic arguments to shell script. The number of arguments differ each time I call the script.

I want to print the arguments using the for loop as below. But not working out.

Code: for (( i=1; i<=$#; i++ )) do   echo $"($i)" done

Code: /bin/sh test.sh arg1 arg2 arg3 Any one please help.