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find out lines in a given file consisting of the following pattern BCAA, BCAAA, BCAAAA, BCAAAAA, BCAAAAAA

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1. The problem statement, all variables and given/known data: find out lines in a given file consisting of the following pattern BCAA, BCAAA, BCAAAA, BCAAAAA, BCAAAAAA

2. Relevant commands, code, scripts, algorithms:

Code: grep BC(A)\{2,6} filename

3.

Is there any way to add lines to the pattern space of sed?

I know a bit about the N flag, but am not able to use it to do what I want which is:

read a file n lines at a time. If I find a match I quit else move to the next line. e.g.

Hi everyone, I am new to shell scripting, and would appreciate your help on following problem.

I need to search a file for a pattern, then get the number of each line that matches the given pattern. Then I need to search those specific line numbers from the first file in a second file and print the entire lines.

I tried with grep -n 'pattern' from the first file, which gives me:

21: pat

I need to remove lines from a text file based on pattern but I need to keep the first n lines of that pattern.

Input

% 1 % 2 % 3 % 4 % 5 text1 text2 text3

output

%1 %2 text1 text2 text3

I used sed /^%/d file but it deletes all the lines starting with %, sed 3,/^%/d doesn't help either. I need to keep first n lines of the pattern and delete the rest

Hi friends,

I am looking for sed command/script that would search for a given fixed pattern on odd lines and then if it matches, prints the matching pattern and the next line.

I have an MRTG configuration file containing some lines starting with the word "Target". Now in such lines there is a pattern starting with the character "#" and end with character ":".

Hi All,

i'm writing a script where i have to grep for a pattern and the 3 lines after the pattern and comment them out.

Note that i have to do this for multiple files, i am able to grep the pattern and the next 3 lines but since solaris does not recognize the -i option, i was wondering if there was any workaround.

Hi I know sed and awk has options to give range of line numbers, but I need to replace pattern in specific lines Something like sed -e '1s,14s,26s/pattern/new pattern/' file name Can somebody help me in this....

I am fine with see/awk/perl Thank you in advance