Match pattern and get lines numbers in a vector

Hi friends,

I am looking for sed command/script that would search for a given fixed pattern on odd lines and then if it matches, prints the matching pattern and the next line.

Hi I know sed and awk has options to give range of line numbers, but I need to replace pattern in specific lines Something like sed -e '1s,14s,26s/pattern/new pattern/' file name Can somebody help me in this....

I am fine with see/awk/perl Thank you in advance

Hi All,

i'm writing a script where i have to grep for a pattern and the 3 lines after the pattern and comment them out.

Note that i have to do this for multiple files, i am able to grep the pattern and the next 3 lines but since solaris does not recognize the -i option, i was wondering if there was any workaround.

Hi Im trying to do the following in sed. I want to delete any blank line at the start of a file until it matches a pattern and then stops.

Here Is a problem I am facing with awk.

Query --> I want to search for a string in a file and print next 15 lines below the matched string.

1.We do not have GNU grep so cannot use grep -A or grep -B commands. 2. Instead of passing the search pattern as a string to awk.

In a bash script using sed how can I remove a block of lines beginning with -pattern a- and ending with -pattern b- where the the contents contains -pattern c- ( or does NOT contain -pattern c-)?

So :

line 1 -pattern a- line 2 line 3 -pattern b- line 4 -pattern a- line 5 -pattern c- line 6 -pattern b-

In this example I want to remove lines 4,5 and 6 (or remove 1,2 and 3 for not cont

i need to search for a pattern from a big file and print everything expect the next 6 lines from where the pattern match was made.

Pipe binary file matches grep results to file I am using grep to match a pattern, but the output is strange.

Code: $ grep -r -o "pattern" * Gives me:

Code: Binary file foo1 matches Binary file foo2 matches Binary file foo3 matches To find the lines before/after, I then have to use the following on each file:

Code: $ strings foo1 | grep -A1 -B1 "pattern" Ho

I need to remove lines from a text file based on pattern but I need to keep the first n lines of that pattern.

Input

% 1 % 2 % 3 % 4 % 5 text1 text2 text3

output

%1 %2 text1 text2 text3

I used sed /^%/d file but it deletes all the lines starting with %, sed 3,/^%/d doesn't help either. I need to keep first n lines of the pattern and delete the rest