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In linux, would it be possible to run a script every day 3 minutes later than the previous day?

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http://unix.stackexchange.com – My first solution to this was to execute date +%Y%m%d%H%M and put that format of numbers into a file, and run the script every minute from cron. Then if the date from the file matches the date command, the script would do something. Then it would update that file for the next day plus 3 minutes. Is there a better way to accomplish this? The result would be that the script would run the first day at (for example) 4:00am then the second day it would run at 4:03am and the third day it would run at 4:06am. It would execute every minute, but only run (if block) at the correct time. Is the questi (HowTos)

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Submitted by Danial on 06/04/2012 – Made popular on 06/04/2012

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Im trying to create a basic mysql dump cronjob in linux.

$ crontab -l

* * * * * sh /tmp/script.sh

then in cat script.sh

$ /home/mysql/bin/mysqldump dbase > /home/backup/date.sql -u root -p root

This will create and overwrite a file date.sql but now how can i get it so it has the date+timestamp as I want to do this every minute.

so i would like it to save the date-.sql rather

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Hi All,

Request your expertise in tackling one requirement in my project,(i dont have much expertise in Shell Scripting). The requirement is as below,

1) We store the last run date of a process in a file. When the batch run the next time, it should read this file, get the last run date from the file.

I have a Paas cron service that only run on minutely, hourly, daily, weekly. I want my script to run o every 15 minutes at 8am, 9am, 10am, 11am, 4pm and 5pm. how do I do that.

Hi all, I need a script to do some date/time conversion. It should take as an input a particular time. It should then generates a series of offsets, in both hour:minute form and number of milliseconds elapsed.

For 03:00, for example, it should give back 04:02:07 (3727000ms*) 05:04:14 (7454000ms), 06:06:21 etc...

How would I go about doing this as a bash script?

I have two time strings; eg. "09:11" and "17:22" on the same day (format is hh:mm). How do I calculate the time difference in minutes between these two?

I have the following bash script lines in a file named test.sh.

Code: #!/bin/bash # # Write Date to cron.log # echo "Begin SSI Load $(date +%d%b%y_%T)" # # Get the latest rates file for processing. # d=$(ls -tr /rms/data/ssi | grep -v "processed" | tail -n 1) filename=$d export filename echo "The file name is $filename."

When I execute ./test.sh

I'm curious if anyone has ideas what may be causing this. I have a PGP script that for whatever reason if I let linux's cron run it automatically, it sends out the final email with attachment with a blank file. If I come in and run in manually everything works fine and the file is populated in the file.

I have this simple script which redirects the output and append it to a file.

filename="/home/ronnie/tmp/hello"

date=$(date) echo "$date" >> $filename

Now, lets suppose I change date=$(date) to date= $(date) which will generate an error.

Input date on script 24 weeks 22 hours ago

How can I allow users to change the date and time in a script? Say the user1 wil login and he will be inputting the desired date (example format below). I will need this script so the user can login and change the date anytime during the day. I will not allow him to use any command except the date change so Im planning to incorporate a menu script on it. Pls help.