I have no idea how to solve this :/

I am making a shell script that will have "shortcuts" to do different tasks and I can't get what I'm doing wrong (this is just a test script)

Code: read cake if [ $cake == "1" ] then echo "1 it is" fi it outputs:

Code: 1: : bad variable namecake test.sh: 27: test.sh: Syntax error: end of file unexpected (expecting "then")

In python this would be easy:

Code: if test_var in ["a","b","c"]: print "Yes" ...but is there a way to do the same in bash?

Heh, working on a bash script to chop up a file based on its filesize.

Using awk variables for regular expressions is working for me in AIX. It is failing for me in SunOS. I don't know why. Can someone explain and/or suggest a fix for the SunOS version?

Here is a little test script. It runs fine in AIX:

Code: $ cat test.ksh #!

Am executing a simple script which read input from csv file and stores in a variable and display it back.

But am facing the following error..

Hi guys...was trying to use while loop and a sentry to prompt user input again if an invalid option was entered...but somehow I got a "while" unmatched error...The code is as below:

Code: #!/system/bin/sh

finsh=0 while [ $finish -ne 0 ] do echo "Please select an option: " echo "1. One" echo "2. Two" echo "3. Three" echo "4.

Hi - I am having an issue with the below code .. What I have is a script test.sh that calls an ssh session to a server (yes, I have public key setup and working).

First, my script:

Code: meow="Wonderful Gentlemen" for file in $(ls *jpg) do         query=$(exiv2 -g Iptc.Application2.FixtureId $file)         jobid=$(echo $query | cut -d" " -f4-)         echo -e "Read $file. Next!"

Hi:

This is a section on a php file running within a a Joomla module.