The following script is meant to output "vmstat" for example every 15 seconds, but for some reason it only does this if there's activity or when I kill the script, in other cases it just sits there.
#!/bin/bash
#!/bin/sh
ps -ef | grep -v grep | grep "vmstat 15" | awk '{ print $2 }' | xargs kill
ps -ef | grep -v grep | grep "iostat 15" | awk '{ print $2 }' | xargs kill
ps -ef | grep -v grep |
I found an SO called using Find/Grep to search files between specific time of day
Based on that and a Unix SE called Grep command to find files containing text string and move them I ended up with:
find . -type f -mtime -20 | grep -v -e " \(0[012345]\|18\|19\|2[0123]\)" | xargs mv -t daytime/
But it's moving ALL the files.
I'm trying to find all files that are of a certain type and do not contain a certain string. I am trying to go about it by piping find to grep -v
example:
find -type f -name '*.java' | xargs grep -v "something something"
This does not seem to work. It seems to be just returning all the files that the find command found.
Hi
Here is the problem ( Exercise 3-3, Using The Shell of The Unix Programming Environment, Kerninghan, Pike, 3rd edition ):
Predict what each of the following grep commands will do, and then verify your understanding.
Code:
grep \$
grep \\$
grep \\\$
grep '\$'
grep '\'$'
grep \\
grep \\\\
grep "\$"
grep '"$'
grep "$"
A file containing these command
When using grep -r you could search in all files with either * or .
and it seems to return the same thing but is it really the same?
Let's say I search for "foo", then I could write
grep -r foo *
or
grep -r foo .
Would anyone try to explain the difference between . and *?
Hello,
When i run this command
Code:
find ./ -type f -print | xargs grep -l 'myWord'
it prints the file name where 'myWord' exists and also something like the below which i want to exclude
Code:
grep: can't open Fields
grep: can't open Search
I tried piping and grep -v 'open' but it did not work.
Thanks in advance
jak
I want to grep a pattern in some files and count the occurrence with the filename. Right know, if I use
grep -r "month" report* | wc -l
it will sum all instances in all files. So the output is a single value 324343. I want something like this
report1: 3433
report2: 24399
....
The grep command will show the filename but will print every instance.
Hello,
My objective is to make a tar file (a backup) of all files smaller then 5M.
This file should exclude file in the backup/YY subdirectory and all hidden
files. Some of the file name contain whitespaces.
I attempted this with the commands below. This resulted in an
empty archive. Taking it piecemeal grep isn't working correctly.
find . -name '.htaccess' -print | xargs grep -il 'sound' | xargs -p sh -c ">{}"
Trying to find some .htaccess files on a host that've been compromised, grep them to make sure they are bad .htaccess (not all on server have been ruined) and blank them out.
All is working, except the last part. Tried many variations of echo > etc.
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