Is there any standard command that will negate the the exit code of another command provided as an argument without using shell features, or starting a shell?
I have a program that does something based on exit code of an system() call. I have another program that returns its status via the exit code. But the program I am calling returns the results opposite from what I want.
I am using a makefile where there is a line like
VAR=$(MVAR) command1;
Now when command1 executes i want VAR to retain the value what is being assigned by MVAR which is required for the successful completion of command1.
But unfortunately VAR contains some default value while executing command1, ie VAR is not able to hold the value assigned during assignment while executing command1.
if same c
I have 2 commands which I want to pipe like so: command1 | command2. When command1 does not output anything at all command2 still outputs. How do I stop
command1 | command2 from outputting when command1 does not output anything?
Concrete example:
function find_string_in_file {
find .
If i execute 'ps' command in shell, i can get some processes marked as '' - they are exited, but parent process don't receive they exit status yet.
Consider this function:
func () {
exit 1
}
Normally when this function is called will cause the script to terminate, which is the intended behaviour. However, if it's executed in a sub-shell, such as in
result=`func`
it will not exit the script. This means the calling code has to check the exit status of the function every time. Is there a way to avoid this? Is this what set -e is for?
Hi All,
I am new to shell sciprting and i have written a small script to get the filename if it exists. I need to capture the file name using the script and i also need the exit status. The problem i am facing is,though my file does not exists, iam getting the exit status as '0'.
I am attempting to do the following in a bash script and am wondering if it is possible:
Time the output of a command (in this case, mysql) using time
Suppress the stdout output of the command
Capture the stderr output of the command in case of an error
Check the exit status code of the command after running it
This is a complex chain and I haven't had much luck getting it all to work together
I just customized my .bashrc to include the exit status of the last command, so I get fancy prompts like
☑ larsmans@host:~$
and I no longer have to re-run commands to see their exit status because I ran some other command in between. This uses $? to determine the exit status.
Title says it all; I cannot run shell commands properly.
Most commands (pwd and my own program) end with an exit code of 1 (permission denied).
The command ls ends with an exit code of 2.
System Note:
Apache is running as apache:apache (user/group)
PHP is not chrooted (AFAIK) if you know a definitive way to find out, please reply
PHP is not in SAFE_MODE
selinux is DISABLED (sestatus says so)
su
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