How to get the days of Particular date?

My first then statement is executing even though there is no match between the variables.

Hi Am using Unix Ksh

Code: I have a two date input as DATE1=02/12/2012 DATE2=30/12/2012 I Need the output as only sunday date Code: 02/12/2012 09/12/2012 16/12/2012 23/12/2012 30/12/2012 can anyone pls help me.. thanks in advance...

Is this code good for this purpose?

Code: <?php $date1 = mktime(0,0,0,01,01,1991); $date2 = mktime(0,0,0,03,22,2012);

$diff = $date2 - $date1; $days = $diff / (60*60*24);

echo ($days . "<br />"); ?>

Hi!

i want to print ot my data of the last seven days with gnuplot. in a script i put my gnuplot-script and at the top i generate my date-variable.

While getting time for a particular date i get negative value. what could be the reason for it.My code like this.

I'm trying desperatly to find a bash or ksh routine that allows me to find for example the previous Monday,Tuesday,Wednesday,... preceding today's date. Additonal it has to work on plain vanilla Solaris X and I don't have the GNU date available.

eg: Today = Thursday 2013/01/17 ; Let's say I want to find the last Monday.

How can i make the date command output yesterday's date, current date and the date 4 days ago, in the following format:

Code: 2012-10-03 code:

Code: date +%  ????

Hi,

I am trying to display future date from the current date but unable to do so in UNIX (not in PERL). For eg: if today is March 5 then I want a variable wherein I can store Mar 7 date, but unable to get the future date from the current date. I have tried many possible ways as mentioned below but all in vain.

Hi Am Using Unix Ksh I have input

Code: DATE1=01/11/2012 DATE2=10/12/2012 need output as count of all sundays between these two dates

Code: for examples Sunday count between DATE1 and DATE2 is 5 Can anyone help me...