Hi All,
I have a quick question with regards to SED syntax, and I hope someone here can help me out.
I have some text based reports in which I would like to strip the "Current Date" from and replace with equivalent number of empty spaces, for every occurrence.
For example, here is what I need to strip:
Hi All,
I have a quick question with regards to SED syntax, and I hope someone here can help me out.
I have some text based reports in which I would like to strip the "Current Date" from and replace with equivalent number of empty spaces, for every occurrence.
For example, here is what I need to strip:
I need a script to search for *.LOG in a directory, output the line after the current date and yesterday's date and also output the next 5 lines after the current date and yesterday's date
I have tried following commands, still no result
Code:
Currentdate=`date -u +"%m/%d/%y"`
awk '/$Currentdate/{getline; print}' *.LOG
The log has data for the whole month for which I need only the
All, I am facing an issue with julian date conversion..
current command:
Code:
echo `date +%Y%j` `cat -n /home/user/FILENAME.dat |awk '{printf "%08s", $2}'`
The above command is working good. But in the above bolded part, it is converting system date to julian date.
Hi,
I am trying to display future date from the current date but unable to do so in UNIX (not in PERL). For eg: if today is March 5 then I want a variable wherein I can store Mar 7 date, but unable to get the future date from the current date.
I have tried many possible ways as mentioned below but all in vain.
Hi,
I need subtract two date values (which are in day of the year format) and the output would give the remaining days. using the command date +"%j" i would get today's 'day of the year' i.e.,
Code:
> date +"%j"
256
Next, i need to take input of a previous date in the format 09/05/2012 and then convert it to 'day of the year format'.
Hi All,
I want to run a script that will search backwards through a text file until it finds a certain string, something like "Date/Time/Eng" and select a string which happens to be a date and save that as a variable.
The line will always be in the following exact format:
Date/Time/Eng.
Hi Guys,
I have a file with following content
Code:
From 20121014 : To 20121014
Number of days : 1
1234
1245
1246
1111
Everyday i run my script i want to modify "To" date on the first line with current date. I have set the current date in script as
Code:
RUN_DATE=`date -u +%Y%m%d`
So i want to replace "To" date with $RUN_DATE.
Hi, I am new to unix and I am doing following steps :
1. Ask user to enter date in mm-dd-yyyy format.
2. show the date user entered from step #1 .
3. convert user enter date into YYYY/MM/DD format.
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