how awk compare output from 'last -x' with file

Hello,

I run F12. Since some days my laptop has become very sluggish. In Mozilla, switching between the tabs takes like seconds instead of fraction of a second. Also minimizing and mximizing windows takes long. Switching between the windows too takes long. Now I can't see the cursor while typing this post.

Code: Kernel  71.0  |####################      |  Reads    12532  Rawin        0 User    17.5  |######                      |  Writes    1179  Ttyout    1376 Wait    10.0  |####       

Hi guys, i already search in this forum and i can't find a way to do this.

Experts, Can you please help how to get the output that are written just below "bad"

Code: calls                  badcalls                nullrecv                439486                  54    &nbsp

In the following program though most of the working part of the program is commented out, it gives seg fault. reducing the value of MAX to say 10000 removes the seg fault. Why is this happening? it should be only 1 MB only. Is 1 MB too big for an array?

#include <stdio.h>

#define MAX 1000010

int main() {

I have a server with these specs :

PHP Code:

Last login: Fri Aug 24 13:26:37 2012 from 118.71.57.107 [root@localhost ~]# free              total       used       free     sh

Code: 1      Petras          Pavardenis      1980            5 08      Linas          Bajoriunas      1970            10 3      Saulius        Matikaitis      1982  &

Dear All,

I have file : input.txt

Code: HANDVEL 2201181                                                1000      180      19      1540    173    1581    316    1652    509&n

Hi buddies !