http://www.unix.com – I am new to shell scripting plz help me to get solution for below requirement If name.sh file is present, message will be displayed as name.sh is present else "name.sh is not present" I have tested below script but getting error. Code: #!/bin/ksh file_found=`ls name.sh` found=`echo $?` if $found -eq 0 then echo "$file_found is present" else echo "name.sh is not present" fi Error Code: bash-2.05$ ./filename.sh ./filename.sh[4]: 0: cannot execute name.sh is not present bash-2.05$ Thankx, Rahul (HowTos)