13

Expect Script Not working with Crontab

view full story
linux-howto

http://www.unix.com – I have the following expect script sitting on a Linux box. === Code: #!/usr/bin/expect -f # # backup.expect # # Expect script to backup a  firewall via a SSH  session # # set firewall    [ lrange $argv 0 0 ] set username    [ lrange $argv 1 1 ] set password    [ lrange $argv 2 2 ] set prompt      [ lrange $argv 3 3 ] set filename    [ lrange $argv 3 3 ] match_max 50000 spawn ssh -l $username $firewall expect "yes/no" { send "yes\r" } expect "assword:" send "$password\r" expect -timeo (HowTos)

ziyi's picture
Submitted by ziyi on 04/08/2012 – Made popular on 04/08/2012

Stories similar to Expect Script Not working with Crontab

check this code

Code: #!/usr/bin/expect   set timeout 5   set Machine [lindex $argv 0]   set Username [lindex $argv 1]   set Password [lindex $argv 2]   spawn telnet $Machine   sleep 1   expect {               -re "(ogin:)|(name:)"  { send "admin\r"             &

Using expect 26 weeks 2 days ago

Hello.

I am trying to debug a script of mine. I am using the ssh-copy-id from a script run by root.

Code: #!/bin/sh # $1 is user_name  $2 is computer adress spawn -noecho  ssh-copy-id $1@$2 ] set timeout 20 send_user "ssh-copy-id started\n" while {1} {     expect {         ^"(Password :)"$ {           &nbsp

I am still learning expect, For the below script I always get This is True as the answer. Tried to debug and does not make sense to me. Not sure, where I am doing the mistake. Need Help!

I have write a script which contains

Code: ssh -p 12345 dcplatform@10.125.42.50 ssh 127.0.0.1 -p 5555 "$CMD" ssh root@$GUEST_IP "$CMD" before I use public key, it works well, now I want to change to "expect", BUT I don't want to change above code and "parameter position"

I can post a expect template can some one help me to modify it

Code: #ca

Code a relic 3 years 18 weeks ago

Code of baul :)

Code: /*  * Hanx [Proyecto Fedora Peru] wth Code  * crc.c - app  *  * This program is private version, for anti-educational purposes and without any  * explicit or implicit warranty; in no event shall the author or  * contributors be liable for any direct, indirect or incidetal damages

If I execute script

Code: #!/usr/bin/expect set pass [lindex $argv 0] spawn encfs -v  {CRIPT_DIR}  {MNT_DIR} -o nonempty expect "*EncFS Password:*" send "$pass\r" expect eof I don't have access to {MNT_DIR}. Sodo user don't have access to.

undue seg fault 3 years 11 weeks ago

In the following program though most of the working part of the program is commented out, it gives seg fault. reducing the value of MAX to say 10000 removes the seg fault. Why is this happening? it should be only 1 MB only. Is 1 MB too big for an array?

#include <stdio.h>

#define MAX 1000010

int main() {

Problem with expect script 20 weeks 3 days ago

Code: expect {         -re "(.*)NEXT PAGE(.*)" {         send "\r\n"         }         exp_continue

Quote:

i just want to put for loop in this code i.e.

argv 3 years 11 weeks ago

Hi guys

I use the following code to check if a user has specified a certain argument:

if (strcmp(argv[i], "-i") == 0) {         // do something } I use the following code to check whether any arguments have been specified (e.g. -i test1) but it gives me a segemtation fault if no arg for -i is specified: