Quoting and escaping is really an important way to influence the way, Bash treats your input. There are three recognized types:
* per-character escaping using a backslash: \$stuff
* weak quoting with double-quotes: "stuff"
* strong quoting with single-quotes: 'stuff'
Quoting and escaping is really an important way to influence the way, Bash treats your input. There are three recognized types:
* per-character escaping using a backslash: \$stuff
* weak quoting with double-quotes: "stuff"
* strong quoting with single-quotes: 'stuff'
I am trying to write a function that I will put on all my machines in order to make it easy to send files at a fixed place on my network.
Here is my script so far.
I understand that one technique for dealing with spaces in filenames is to enclose the file name with single quotes: "'".
Why is it that the following code called, "echo.sh" works on a directory containing filenames with spaces, but the program "ls.sh" does Not work, where the only difference is 'echo' replaced with 'ls'?
echo.sh
#!/bin/sh
for f in *
do
echo "'$f'"
done
Produces:
'a b c'
Hey guys,
I'm having some issues escaping quotes and getting the following line to run in perl. The quotes are really messing me up.
Code:
system (" awk 'BEGIN{FS="/t";OFS=","} {print \$1,$fieldNum}' $file > output.csv ");
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I recently had trouble with some regex on the command-line, and
found that for matching a backslash, different numbers of
characters can be used. This number depends on the quoting used for
the regex (none, single quotes, double quotes).
When i use sed and use braces like this
sed -re 's/top([0-9]+)//g'
I works for this but i have seen sometimes i need to escape the braces and sometimes it works without escaping. why is that
Why does \w don't work with awk
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