Creating Printing Program in bash

Hi,

I am getting this error while running the following code.

Code: i=`awk '{print $2}' test1.txt` j=`awk '{print $4}' test1.txt` k=`awk '{print $6}' test1.txt` if [ $i =="Yes" && $j =="Yes" && $k =0 ]; then echo "Up." else echo "down" fi rm -f test.txt test1.txt error is this:

Code: line 12: [: missing `]' Please suggest.

I was just curious about how to sum the total file size of a certain type of file. For instance:

Code: $find . -name "*.aif" will print out the paths to each .aif file. Instead of printing, how could one sum the total space used by all of the aif files?

Suppose your piping a path into xargs and want to print the name along with the total size:

Code: find . -maxdepth 1 | xargs -I {} echo "{} [`du -hs {} | sed 's/ [[:alnum:][:punct:]]*//g'`]" This won't work because {} ceases having its special meaning within the ``. How to preserve it?

All, Q: how would I add some escape codes to an interface that i have setup t print.? Goal: to switch from NLQ to Util modes. back and forth.

Scenerio: SCO OS 5.05 PRINTER: OKI Data 320 or similar. printer is called "test"

What I have done thus far.

Hi, I wanted to create a control file with data in it. Also wanted to append more points like 1)Row count, then print the first field 2)first line of the file 3)last line of the file I started with this:-

Code: ls -ltr *.*| awk ' { print $9 "|" $7 $6 $8 "|" $5 } ' sed -n '1p'; sed -n '$p';

Moderator's Comments:

Hello,

i try to create dir in C like that:

Code: mkdir("/home/chercheur/1"); but when i try to open this directory: i have this message

Code: Vous n'avez pas les permissions nécessaires pour afficher le contenu de «*1*». have you an idea please Thank you.

Moderator's Comments:

Hi,

My input file as follws $ cat 1.txt -------

Code: a aa aaa 11 b bb bbb 22 I am able to extract first and last column of a given line as follows.

Code: $ nawk '{print $1}' FS= RS= 1.txt | awk '{ $NF = ""; print }' a

Code: $ nawk '{print $1}' FS= RS= 1.txt | awk '{ print $NF}' 11

however, the same is not working by using shell script.

Hi I wrote shell script to do the flowing count from 5 and down but doesn’t work please see my program

Code: #Bash

x=0 y=10

while  (( x < y )) do (( x = x + 1 ))

grep -A $x 5 numbers >>file4.txt done these the output

Code: 5 6 5 6 7 5 6 7 8 5 6 7 8 9 5 6 7 8 9 10 5 6 7 8 9 10

5 6 7 8 9 10

Moderator's Comments:

Dear friends,

I have a file with the text:

Code: href="/archive/ip=x.x.x.x">M</a></td> I want to extract just the IP number.