13

COMMAND NOT FOUND

view full story
linux-howto

http://www.unix.com – Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted! 1. The problem statement, all variables and given/known data: Trying to run script but everytime I do I get teh following error message line 4: [1: command not found I have attempted different version but still come up with same results. 2. Relevant commands, code, scripts, algorithms: #!/bin/bash count=1 echo "start of the program" while [$count -1e 10] do echo "Loop #$count" sleep 10 count=$[count+1] done echo "end of the program" (HowTos)

more's picture
Submitted by more on 04/11/2012 – Made popular on 04/11/2012

Stories similar to COMMAND NOT FOUND

Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!

1. The problem statement, all variables and given/known data:

A script that takes any number of directories as command line arguments and then lists the contents of each of these directories.

enf of line error 34 weeks 4 hours ago

Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!

1. The problem statement, all variables and given/known data:

Code: #/bin/sh -xv #Author: Lauren Buecker #Date: September 28 2012 #Class COP3353 #Assignment: Assignment 4 echo "There are "$#" pamaters" if ($# !

Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!

1. The problem statement, all variables and given/known data:

i have the output of a csh script piped to an awk script.

Hello Friends, [In bash] I am not able to solve something which looks silly..after spending some time around it, thought of positing it here. I want to get $2, $3... into user.

i have something like this

Code:

tablesName="abc def hij akn ...

hi my code is something like

Code:   count=0     echo "oracle TABLESPACE NAME  nd TARGET"

      while [ loop condition ]       do               count=`expr $count + 1`

            (1)    tts_space_name$count=`echo $tts | cut -d "," -f$cou

Problems with if statement 27 weeks 6 days ago

Hi guys..i'm totally new to linux shell scripting and i have written a simple script that allows to poll a directory and when there is at least one file, it is moved to another directory. But i have an error in the if statement " Syntax error: "then" unexpected (expecting "done")"

Code: #!/bin/bash

while true do count=$(find /home/dirA -type f | wc -l)

Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!

1.

I want to run my shell script to the limit number.Suppose I know in advance that MAX=5 then I want that my script run 5 times only.Something like below Code: [st@VHLD rohit]$ vi testingMAX=5COMMAND="ssh -l stpuser VHLDVWSAD001 /projects/st/utils/deploy/deployall.sh >/dev/null 2>&1 &" ; sleep 20;count=0while [ $count -le $MAX ]docount=`expr $count + 1`echo `COMMA