1

In a bash script, using the conditional "or" in an "if" statement

view story
linux-howto

http://unix.stackexchange.com – This question is a sequel of sorts to my earlier question. The users on this site kindly helped me determine how to write a bash for loop that iterates over string values. For example, suppose that a loop control variable fname iterates over the strings "a.txt" "b.txt" "c.txt". I would like to echo "yes!" when fname has the value "a.txt" or "c.txt", and echo "no!" otherwise. I have tried the following bash shell script: #!/bin/bash for fname in "a.txt" "b.txt" "c.txt" do echo $fname if [ "$fname" = "a.txt" ] | [ "$fname" = "c.txt" ]; then echo "yes!" else echo "no!" fi done I obtai (HowTos)

Songlist's picture
Submitted by Songlist on 09/08/2012

Stories similar to In a bash script, using the conditional "or" in an "if" statement

In bash, I know that it is possible to write a for loop in which some loop control variable i iterates over specified integers. For example, I can write a bash shell script that prints the integers between 1 and 10:

#!/bin/bash

for i in {1..10} do echo $i done

Is it possible to instead iterate over a loop control variable that is a string, if I provide a list of strings?

I think I know what this is doing, but the 'eval' is confusing

Code: fname=$(echo ${lineItem} | awk 'BEGIN {FS=";"}{print $1}') fname=${fname%%+([[:space:]])} fname=${fname##+([[:space:]])} eval "fname=${fname}" The first line extracts the contents of the line preceeding the ";" 2nd & 3rd lines trim the value (I think ..

I am suppose to make a program that cuts the extension off of a file. It uses that .ext to decide which program needs to be used to open the file. This only finds the name of the program from a list of programs I made. My problem is when it has the name of the program it needs to use, how can I make the program open the file with code in the script.

I am suppose to make a program that cuts the extension off of a file. It uses that .ext to decide which program needs to be used to open the file. This only finds the name of the program from a list of programs I made. My problem is when it has the name of the program it needs to use, how can I make the program open the file with code in the script.

Hey , guys I am new to shell programing ,, so need a help from you guys ...

I have to write a shell script that accepts file name or directory name from the user if it is a directory then throw an error if it is a file then give the user two options . 1.overwrite the content 2.append the content

Here is my program ..

unusual problem with cp command 43 weeks 3 hours ago

I have made a simple script to zip a file then first copy it to a specific directory using cp command then move it to another directory. Files are getting generated at regular intervals in the dir. /one/two/three/four/.

Fun bash script I made 47 weeks 5 days ago

Ok so I got a little bored and desided to make a fun little bash script that you can use to scare Linux neewbies :)

Here is the code:

Quote:

#!/bin/bash clear echo "Formating disk(s): " /dev/sd* sleep 2 echo "Initialising..." sleep 2 echo "Are you sure you want to format these disks?" # Declare variable choice and assign value

going through advanced bash scripting guide example 3.3 running a loop in background, i found this :

#!/bin/bash # background-loop.sh for i in 1 2 3 4 5 6 7 8 9 10 # First loop. do echo -n "$i " done & # Run this loop in background. # Will sometimes execute after second loop. echo # This 'echo' sometimes will not display. for i in 11 12 13 14 15 16 17 18 19 20 # Second loop. do echo -n "$i "

dialog options array 36 weeks 1 day ago

Hi everyone, I have a bash script that launches a dialog interface. I want to read values from a .csv file to build the options selection but it is just not working right. Maybe someone can point out what Im doing wrong.