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awk sub command in Unix

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http://www.unix.com – Hi, I am new to unix shell script and I have some trouble on the awk sub I would like to pick the Date "July 10 2012" into $corr_date by using sub() function, but it is not successful. The inputted text file: pic.*.txt July 10 2012 20:30:50 , 1234567.jpg July 10 2012 20:30:52 , 5648978.jpg July 10 2012 20:30:53 , 6405789.jpg Code: #!/bin/ksh curr_date=`date +"%B %d %Y"` for i in `ls -1 pic.*.txt`   do     Date=`tail -1 $i |awk 'BEGIN {FS=","} {print $1}'`     corr_date=`awk '{sub(/[0-9]+:[0-9]+:[0-9]+/,"") ; print;}' (HowTos)

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Submitted by robot1 on 07/10/2012 – Made popular on 07/10/2012

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Hi, I am new to unix shell script and I have some trouble on the awk sub

I would like to pick the Date "July 10 2012" into $corr_date by using sub() function, but it is not successful.

The inputted text file: pic.*.txt July 10 2012 20:30:50 , 1234567.jpg July 10 2012 20:30:52 , 5648978.jpg July 10 2012 20:30:53 , 6405789.jpg

Code: #!/bin/ksh

curr_date=`date +"%B

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