awk Help - Comparison Operator problem

Hi,

I have a issue, I need to loop through a comma delimited file and check for the length which exceeds specified length , if Yes truncate the string. But my problem is , I do not have to check for all the fields and the field lenght is not same for all the fields.

For ex:

Say my line ahjdh,dfhkajhdf,adhklf,eiour

say I need to check length only for 2nd and 4th and max length for 2nd is 6

I am trying to trim spaces for the fixed width file starting from location 129 and of length 20.

I am expecting only around 40 records that will have length greater than 9. But i am getting around 4000 records.

Please help me correct the following.

Code: nawk '{if (a=length(gsub(/ */,"",substr($0,129,20)))>9); print $a }' testfile |wc -l

Running below line gives 3957 as length of longest line in file 20121119_SRMNotes_init.dat

Code: awk ' { if ( length > 3950 ) { x = length } }END{ print x }' 20121119_SRMNotes_init.dat While wc -L 20121119_SRMNotes_init.dat gives output as 4329. Why is there a difference between these two commands.

Thanks

Hello

I'm manipulating a file, taking certain variables & printing them to an output file using awk (actually nawk because I'm using -v).

I now want to take a field from the input file & expand it to a pre-defined length by preceding the string with spaces.

I need a script that will run in unix to:

1) Read and input file with 1 column that contains for ex: 0123456789 1234567890 ...etc 2) Checks the first column if it is: a. Numeric from 0 - 9 b.

I was wondering if I could use AWK to print from the nth character position to nth for all records in the file.

All I have been doing is printing/copying fields rather than characters. I found a way to print lines greater/less/equal to a character length which led me to believe there is a way to do this in awk.

If this can't be done in awk, then how could it be done?

Thanks!

I have a log-file where at the end of a series of lines you can see if this block is relevant now I'm looking for a command like sed to delete de blocks ending with "Content-Length: 0" and beginning with the last "--" before this line.

I tried sed -n "/--/,/Content-Length: 0/d" but this takes the first "--" and the first "Content-Length: 0" and deletes it.

ex :

line 1 "--" line 2 line 3 "

I have a log-file where at the end of a series of lines you can see if this block is relevant now I'm looking for a command like sed to delete de blocks ending with "Content-Length: 0" and beginning with the last "--" before this line.

I tried sed -n "/--/,/Content-Length: 0/d" but this takes the first "--" and the first "Content-Length: 0" and deletes it.

ex :

line 1 "--" line 2 line 3 "

Hi,

The record length may be differ in afile. I want to display the records if the record length is not equal to 50 using sed/awk command.

Thanks in Advance