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AWK FS with ignore space option

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linux-howto

http://www.unix.com – Hi, i have in a situation to get the variables which are having a "|" delimiter and each variable may or may not have spaces, so how can i skip the spaces on the string and print the string as it is. For example: line = "|Hello world|Hello|Hi Guys| read x y z <<<$(echo "$line" | awk -F"|" '{print $1,$2,$3}') echo -e "$x" (should be 'Hello world') buts it's printing only Hello. Could some one please help me. (HowTos)

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Submitted by robot1 on 08/29/2012

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Please help me!...

I have a string " test1 test2 test3 ". There are two spaces before "test1"; There are four spaces between "test1" and "test2"; there are two spaces between "test2 and "test3".

I want to extract a substring "2 test3" using positions.

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Code: ************ str=" te